Math, asked by parulprajapati82, 10 months ago

3/2x^2y+4/5y-1/3x^2yz from 12/5x^2yz-3/5xyz+2/3x^2y

Answers

Answered by asahilthakur

4

Answer:

Step-by-step explanation:

(12/5x²yz-3/5xyz+2/3x²y) -(3/2x²y+4/5y-1/3x²yz)

=12/5x²yz-3/5xyz+2/3x²y-3/2x²y-4/5y+1/3x²yz

=41/15x²yz-3/5xyz-4/5y-5/6x²y

Answered by Anonymous

3

Answer:

here is your answer.......

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