Question

(3/2x+7/5)^2
$( \frac{3}{2}x + \frac{7}{5})^{2}$
explain briefly​

Answer 1

EVALUATION★

$= ( \frac{3}{2} x + \frac{7}{5} ) {}^{2}$

we know that

$= > (a + b) {}^{2} =a {}^{2} + b {}^{2} + 2ab$

let's

• $= > a = \frac{3}{2}x \\ \\ = > b = \frac{7}{5}$

solve

$= = > ( \frac{3}{2}x + \frac{7}{5} ) {}^{2} \\ = (\frac{3}{2} x) {}^{2} + ( \frac{7}{5} ) {}^{2} + 2 (\frac{3}{2}x)( \frac{7}{5} ) \\ \\ = \frac{9}{4}x {}^{2} + \frac{49}{25} + \frac{21}{5} x \\ \\ = \frac{9}{4} x {}^{2} + \frac{21}{5} x + \frac{49}{25}$

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I hope it helps you