[ 3^3 - (1/2)^-3 × 1/19 ]
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Question :- [3^3-(1/2)^-3×1/19]
Solution :-
Note : Apply (a/b)^-3 = (b/a)^3
=》 27-(2/1)^3 × 1/19
=》 27-(2^3/1^3) × 1/19
=》 27-(8/1) × 1/19
=》27/1 - 8/1 × 1/19
L.C.M. of 1 and 1 = 1×1 =1
=》 (27-8)/1
=》 19/1
=》19
Therefore,[3^3-(1/2)^-3-1/19] = 19
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Solution :-
Note : Apply (a/b)^-3 = (b/a)^3
=》 27-(2/1)^3 × 1/19
=》 27-(2^3/1^3) × 1/19
=》 27-(8/1) × 1/19
=》27/1 - 8/1 × 1/19
L.C.M. of 1 and 1 = 1×1 =1
=》 (27-8)/1
=》 19/1
=》19
Therefore,[3^3-(1/2)^-3-1/19] = 19
■■■ HOPE THIS HELP U ■■■
●●●MARK IT AS BRAINLIEST●●●
▪¤¤▪ PLZZZ....▪¤¤▪
☆☆THANKS....☆☆
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