Math, asked by sheetalbhavsar19280, 1 month ago

(3√3+2√2)²
(3 \sqrt{3 } + 2 \sqrt{2} ) ^{2}

Answers

Answered by mpd20700
1

Answer:

(3√3 + 2√2)²

{using the identity : (a + b)² = a² + b² + 2ab}

= 9(\sqrt{3}) ^{2} + 4(\sqrt{2}) ^{2} + 2(\sqrt{3}  )(\sqrt{2})\\

= 9×3 + 4×2 + 2√6

= 27 + 8 + 2√6

= 35 + 2√6

Answered by shashi32254
1

Answer:

(3√3)^2+(

2√2)^2+

2*3√2*2√2

Step-by-step explanation:

27+8+12√6

35+12√6

this is right answer

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