3, 3+√2, 3+2√2 , 3+3√2 find the common difference
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common difference, d = √
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3, 3 + √2, 3 + 2√2, 3 + 3√2, ….
Here, the first term, a1 = 3
Second term, a2 = 3 + √2
a3 = 3 + 2√2
Now, common difference = a2 – a1 = 3 + √2 – 3 = √2
Also, a3 – a2 = 3 + 2√2 –(3 + √2) = 3 + 2√2 – 3 – √2 = √2
Since, the common difference is same.
Hence the terms are in Arithmetic progression with common difference, d = √2 .
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