Math, asked by ramanrai, 1 year ago

3/√3-√2+√5rationalize it

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Answered by Leam
1
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Answered by hukam0685
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 \frac{3}{ \sqrt{3} -  \sqrt{2} +  \sqrt{5}   }  \\ \frac{3}{ \sqrt{3} -  \sqrt{2} +  \sqrt{5} } \times  \frac{( \sqrt{3} -  \sqrt{2}  -  \sqrt{5}  }{( \sqrt{3} -  \sqrt{2}  -  \sqrt{5} }  \\  =  \frac{3( \sqrt{3}  -  \sqrt{2} -  \sqrt{5})  }{( { \sqrt{3} -  \sqrt{2}  )}^{2}  - ( { \sqrt{5}) }^{2} }  \\  =    \frac{3( \sqrt{3} -  \sqrt{2}  -  \sqrt{5})  }{3 + 2 - 2 \sqrt{6} - 5 }  \\  = \frac{3( \sqrt{3} -  \sqrt{2}  -  \sqrt{5})  }{- 2 \sqrt{6}  }  \\ \frac{3( \sqrt{3} -  \sqrt{2}  -  \sqrt{5})  }{- 2 \sqrt{6}  }  \times  \frac{ \sqrt{6} }{ \sqrt{6} } \\  = \frac{3( \sqrt{18}  -  \sqrt{12}  -  \sqrt{30}) }{ - 12}  \\  =   \frac{(3 \sqrt{2}  - 2 \sqrt{3}  -  \sqrt{30} }{ - 4} \\  =  \frac{2 \sqrt{3}  - 3 \sqrt{2} +  \sqrt{30}  }{4}
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