Question

3(3 - 2q)(3q+3)(q-2)

Answer 1

Step-by-step explanation:

(9 - 6q) (3q + 3)(q-2) = 0

(27q + 27 - 18q² - 18q)( q-2) = 0

27q² - 54q + 27q - 52 - 18q³ + 36q² - 18q² + 36q = 0

45q² - 9q - 18q³ - 52 = 0

18q³ - 45q² + 9q + 52 = 0

And by using cubic formula we get q= 0.856262

Hope this helps