Math, asked by windy100, 1 year ago

3×√(3)−3×√(5)−3×√(2)+√(45)+√(75)+√(30)

how to solve it plz help.​

Answers

Answered by Milieth
0

3×√(3)-3×√(5)-3×√(2)+√(45)+√(75)+√(30) = 3√(3)-3√(5)-3√(2)+√(9×5)+√(25×3)+√(3×2×5)

= 3√3-3√5-3√2+3√5+5√3+√30

= -3√5+3√5+3√3+5√3-3√2+√30

= √5(-3+3)+√3(3+5)-3√2+√30

= √5(0)+√3(8)-3√2+√30

= 0+8√3-3√2+√30

= 8√3-3√2+√30

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