3, 3, 4 ,5 = 63, 8 ,4, 4, 3 =51, 9 ,7 ,5, 9 = ?
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•Given:-
3, 3, 4 ,5 = 63, 8 ,4, 4, 3 =51,
•To find:-
9 ,7 ,5, 9 = ?
•Solution:-
According to the first series
we can explain it ,like
3 + 3 + 4 + 5(at first we have to add all numbers in this given series)
( we have to multiply 2 with the number which is formed)
=15×2
[We have to minus 2² {format is n²....(n+2)²...(n+2+2)².....}and 5 which is the last number of the series]
= 30 - 2² - 5
(we have to multiply 3 with it)
= 21 × 3
= 63
& now in
2nd one.
8 + 4 + 4 + 3 = 19 × 2
= 38 - 4² - 5[as it is following the format n²....(n+2)²...(n+2+2)².....]
= 17 × 3
= 51
So the final answer is
In
3rd one(according to the format)
9 + 7 + 5 + 9 = 30 × 2
= 60 - 6² - 5
= 19 × 3
= 57
So the final series is
3, 3, 4 ,5 = 63, 8 ,4, 4, 3 =51,
9 ,7 ,5, 9 = 57
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