√3(3√48+9√27)-2√3(2√75-√300)
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Hi ,
√48 = √( 4 × 4 ) × 3 = 4√3
√27 = √ ( 3 × 3 ) × 3 = 3√3
√75 = √( 5 × 5 ) × 3 = 5√3
√300 = √ ( 10 × 10 ) × 3 = 10√3
Now
√3(3√48+9√27)-2√3(2√75-√300)
= √3[ 3(4√3) + 9(3√3)]-√3[ 2(5√3)-10√3 ]
= √3 [12√3 + 27√3 ] - √3 [ 10√3 - 10√3 ]
= √3 ( 39√3 ) - √3 × 0
= 3 × 39
= 117
I hope this helps you.
:)
√48 = √( 4 × 4 ) × 3 = 4√3
√27 = √ ( 3 × 3 ) × 3 = 3√3
√75 = √( 5 × 5 ) × 3 = 5√3
√300 = √ ( 10 × 10 ) × 3 = 10√3
Now
√3(3√48+9√27)-2√3(2√75-√300)
= √3[ 3(4√3) + 9(3√3)]-√3[ 2(5√3)-10√3 ]
= √3 [12√3 + 27√3 ] - √3 [ 10√3 - 10√3 ]
= √3 ( 39√3 ) - √3 × 0
= 3 × 39
= 117
I hope this helps you.
:)
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