Question

3.30g of Zinc is dissolved in Hydrochloric acid, producing zinc chloride $ZnCl_{2}$ and hydrogen gas
a)Write a balanced equation using moles
b)How many moles of zinc chloride does the reaction produce?
c)What mass of zinc chloride does the reaction produce

Answer 1

Answer:

For a: The balanced chemical equation is written below.

For b: The moles of zinc chloride produces is 0.05 moles

For c: The mass of zinc chloride produces will be 6.815 grams.

Explanation:

• For a:

The chemical equation for the reaction of zinc metal with hydrochloric acid follows:

$Zn+2HCl\rightarrow ZnCl_2+H_2$

By Stoichiometry of the reaction:

1 mole of zinc metal reacts with 2 moles of hydrochloric acid to produce 1 mole of zinc chloride and 1 mole of hydrogen gas

• For b:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$      .....(1)

Given mass of zinc = 3.30 g

Molar mass of zinc = 65.4 g/mol

Putting values in equation 1, we get:

$\text{Moles of zinc}=\frac{3.30g}{65.4g/mol}=0.05mol$

By Stoichiometry of the reaction:

1 mole of zinc produces 1 mole of zinc chloride

So, 0.05 moles of zinc metal will produce = $\frac{1}{1}\times 0.05=0.05mol$ of zinc chloride

Hence, the moles of zinc chloride produces is 0.05 moles

• For c:

Calculating the mass of zinc chloride by using equation 1:

Moles of zinc chloride = 0.05 moles

Molar mass of zinc chloride = 136.3 g/mol

Putting values in equation 1, we get:

$0.05mol=\frac{\text{Mass of zinc chloride}}{136.3g/mol}\\\\\text{Mass of zinc chloride}=(0.05mol\times 136.3g/mol)=6.815g$

Hence, the mass of zinc chloride produces will be 6.815 grams.