Question

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What is the time period of oscillation of a simple pendulum mounted in a cabin that is freely falling under gravity?
CLASS 11 CBSE

Answer 1

Answer:

Given : A simple pendulum is falling freely under gravity.

The pendulum is mounted in a cabin.

Calculation :

First of all, you need to remember the formula of time period for a simple pendulum .

T = 2π *√(l/g),

where , l is the length of the string, g refer to the acceleration experienced by the pendulum (mostly gravity).

Now, when it is freely falling , the net acceleration experienced (reaction forces) = g -g = 0 (zero) m/s^2

So time period

= 2π *√(l/0)

= 2π *√(l/0)= infinity

Answer 2

Answer:

During free fall the body feels weightlessness inside the lift. Hence g = 0. So time period T = 2π(L/g)½ = 2π(L/0) ½ = ∞.