Question

3√3a³ - 5√5a³ factorise​

Answer 1

SOLUTION :

GIVEN :

(3√3a)³-(5√5a)³

STEPS :

(3√3a-5√5a)((3√3a²)+(5√5a²)+(3a√3×5a√5))

a(3√3-5√5)(27a²+125a²+15a²√15)

a³(3√3-5√5)(27+125+15√15)

So , the answer for given question is a³(3√3-5√5)(27+125+15√15)

NOTE :

Learn all the formulas perfectly to solve this type of problems.

Check the positive and negative signs properly.

Surd is a form of irrational number.

Surds cannot be written in the form of whole numbers.

Surds are always written under roots.

If we multiply or add or divide or subtract any surds , the result may be rational or irrational.

Answer 2

Answer:

a²(3√3 - 5√5)(152 + 15√15), a³(3√3 - 5√5)

Step-by-step explanation:

(3√3a)³ - (5√5a)³

We know that a³ - b³ = (a-b)(a²+ab+b²)

So, we have (3√3a - 5√5a)((3√3a)² + (5√5a)² + (3a√3 × 5a√5))

= (3√3 - 5√5)(27a² + 125a² + 15a²√15)

= a²(3√3 - 5√5)(27+ 125 + 15√15)

= a²(3√3 - 5√5)(152 + 15√15)

However if you question is: 3√3a³ - 5√5a³ and not whole squares, then a³ can be taken common to get a³(3√3 - 5√5).