Question

3/3x-5 –2/4x-7=6/7(4x-7)+7/9(3x-5)​

Answer 1

Answer:

x=4

Step-by-step explanation:

Given that

$\dfrac{3}{3x-5}-\dfrac{2}{4x-7}=\dfrac{6}{7(4x-7)}+\dfrac{7}{9(3x-5)}$

Now lets arrange the factors

$\dfrac{3}{3x-5}-\dfrac{7}{9(3x-5)}=\dfrac{6}{7(4x-7)}+\dfrac{2}{4x-7}$

Now by solving this above equation,we get

$\dfrac{20}{3x-5}=\dfrac{20}{7(4x-7)}$

So from we can say that

7(4x-7) = 9 (3x-5)

28x - 49= 27x -45

So x=4

Answer 2

Answer:

Hh

Gjv

Step-by-step explanation:

I solve the problem