Question

3+4=19
5+6=41
2+8=66
5+1=6
Then 1+3= ?

Answer 1

The values of the given series 3+4 = 19, 5+6 = 41, 1+3 = ??? is 7.

To find:

Give the Answer if 3+4 = 19, 5+6 = 41, 1+3 = ?

Solution:

Given: 3+4 = 19, 5+6 = 41, 1+3 = ???

3+ 4 = 19

Now, 3+4=7 \text { and } 3 \times 4=123+4=7 and 3×4=12 . If we add 7 + 12, we get 19.

Hence, addition of two given numbers i.e. on L.H.S. + multiplication of given two numbers i.e. on L.H.S. = required answer on R.H.S.

Likewise, 5 + 6 = 41

5+6=11 \text { and } 5 \times 6=305+6=11 and 5×6=30 . If we add 11 + 30, we get 41.

1+3 = ???

\bold{1+3=4 \text { and } 1 \times 3=3}1+3=4 and 1×3=3 . If we add 4 + 3, we get 7.

Hence, 1 + 3 = 7.

Answer 2

Answer:

3+4=19=(3+4²)

5+6=41=(5+6²)

2+8=66=(2+8²)

5+1=6=(5+1²)

1+3=10=(1+3²)

?=10