(√3)^-4*(√3)^6*(√3)^0
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(√3)^ - 4 × ( √3)^6 × (√3)^0
In this the bases are same so the powers get added up
therefore we get,
= (√3)^ - 4 + 6 + 0
= (√3)²
= √3 ×√3
= 3
hope it helps
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Answered by
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your answer at the end is
3
....,......
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