Question

3/4 (7x-1)-(2x-1-x/2)=x+3/2

Answer 1

$\frac{3}{4} (7x - 1) - \frac{(2x - 1 - x)}{2} = x + \frac{3}{2} \\ \frac{3(7x - 1)}{4} - \frac{2x - 1 - x}{2} = x + \frac{3}{2} \\ \frac{21x - 3}{4} - \frac{2x - x - 1}{2} = x + \frac{3}{2} \\ \frac{21x - 3}{4} - \frac{x - 1}{2} = x + \frac{3}{2} \\ \frac{21x - 3}{4} - \frac{x - 1}{2} = x + \frac{3}{2} \\ \frac{21x - 3 - 2(x - 1)}{4} = x + \frac{3}{2 } \\ \frac{21x - 3 - 2x + 2}{4} = x + \frac{3}{2} \\ \frac{9x - 1}{4} = x + \frac{3}{2} \\ 9x - 1 = x + \frac{3}{2} \times 4 \\ 9x - 1 = x + 3 \\ 9x - x = 3 + 1 \\ 8x = 4 \\ x = \frac{4}{8} \\ x = \frac{1}{2}$

Answer 2

Answer:

x= 1

Step-by-step explanation:

3/4(7x - 1) - [2x - (1 - x)/2] = (x + 4)/2

(21x - 3)/4 - [4x/2 - (1 - x)/2] = (x + 4)/2

(21x - 3)/4 - (5x - 1)/2 = (x + 4)/2

(21x - 3)/4 - (10x - 2)/4 = (2x + 8)/4

21x - 3 - 10x + 2 = 2x + 8

11x - 1 = 2x + 8

9x = 9

x = 1

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