Question

(3/4 a Square+3 b square) and 4(a square-2/3 b square)

Answer 1

$\mathbf{\frac{19}{4}a^{2}+\frac{1}{3}b^{2}}$

Step-by-step explanation:

1. $\mathbf{\left ( \frac{3}{4}a^{2}+3b^{2} \right )+4\left ( a^{2}-\frac{2}{3}b^{2} \right )}$

2. After opening the bracket

 $\mathbf{\frac{3}{4}a^{2}+3b^{2}+4\times a^{2}-4\times \frac{2}{3}b^{2}}$

 

 $\mathbf{\frac{3}{4}a^{2}+3b^{2}+4a^{2}-\frac{8}{3}b^{2}}$

3.

 $\mathbf{\frac{3}{4}a^{2}+4a^{2}+3b^{2}-\frac{8}{3}b^{2}}$

 after taking common a and b, we get

 $\mathbf{\left ( \frac{3}{4}+4 \right )a^{2}+\left ( 3-\frac{8}{3} \right )b^{2}}$

 

 $\mathbf{\left ( \frac{3+16}{4} \right )a^{2}+\left (\frac{9-8}{3} \right )b^{2}}$

So

 $\mathbf{\left ( \frac{19}{4} \right )a^{2}+\left (\frac{1}{3} \right )b^{2}}$

Answer 2

Answer:

$3a {}^{4} + 10a {}^{2} b {}^{2} - 8b {}^{4}$