Question

3.4 g H202 is present in its 112 ml solution. Volume strength of this solution is​

Answer 1

Answer:

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Answer 2

Answer:

The volume strength of the solution is $99.9V$

Explanation:

Given,

The mass of $H_{2}O_{2}$ = $3.4g$

The volume of the solution = $112 ml$ = $0.112L$

The solution's volume strength =?

As we know,

• Strength = $\frac{Mass}{Volume (L)}$ = $\frac{3.4}{0.112}$ = $30.35 g/L$

The reaction of dissociation of $H_{2}O_{2}$ follows as:

• $H_{2}O_{2} \rightarrow H_{2}O + O_{2}$

After balancing the equation:

• $2H_{2}O_{2} \rightarrow 2H_{2}O + O_{2}$
• $2 moles$                 $22.4 L$ at NTP ( Normal temperature and pressure )

From this, we can say that, $2\times 3.4g$ of $H_{2}O_{2}$ produces $22.4 litres$ of oxygen gas at NTP.

Thus,

• $6.8g$ of $H_{2}O_{2}$ = $22.4 litres$ of oxygen gas
• $1g$ of $H_{2}O_{2}$ = $\frac{22.4}{6.8} litres$ of oxygen gas
• $30.35 g$ = $\frac{22.4}{6.8} \times 30.35$ = $99.9$ of volume strength.

Thus the volume strength = $99.9V$.