Math, asked by sindhusharavuri392, 1 year ago

Diagonals of a parallelogram WXYZ intersect each other at point O. If ∠XYZ=135° then what is the measure of ∠XWZ and ∠YZW ? If L(OY)= 5 cm then L(WY)= ?

Answers

Answered by amitnrw
66

Answer:

∠XWZ  = 135°

∠YZW = 45°

WY = 10 cm

Step-by-step explanation:

In a parallelogram opposite angles are Equal

and sum of adjacent angle = 180°

∠XYZ=135°

∠XWZ  is opposite to ∠XYZ

=> ∠XWZ  = ∠XYZ = 135°

=> ∠XWZ  = 135°

∠YZW is adjacent to ∠XYZ

=> ∠YZW + ∠XYZ = 180°

=>  ∠YZW + 135° = 180°

=> ∠YZW = 45°

Diagonals of a parallelogram bisect each other

hence OY = OW

WY = OY + OW

WY = OY + OY

WY = 2 * OY

WY = 2 * 5

WY = 10 cm

Answered by yograj999
26

Step-by-step explanation:

WXYZ is a parallelogram.

XYZ = XWZ.......( the opposite angle of a parallelogram

are congruent )

But, XYZ = 135°

i.e. XWZ = 135°

XYZ + YZW = 180°...........( Interior angle )

135° + YZW = 180°

YZW = 180° - 135°

YZW = 45°

Also,

OY = ½ × WY..........( the diagonal of a parallelogram

bisect each other )

5 = ½ × WY

5 × 2 = WY

WY = 10 cm.

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