Question

3.42 grams of sucrose is dissolved in 18 gram of water . calculate oxygen atoms in the solution

Answer 1

Answer:

• 6.68 × 10²³ oxygen atom in the solution

Given :

• 3.42 g of sucrose

• 18 g of water

To Find :

• The number of oxygen atoms in the solution = ?

Explanation:

Number of moles of sucrose,

= Mass of substance/Molar mass

Substituting the values, we get

Number of moles of sucrose = 3.42g/342 g mol ¯¹

= 0.01 mol

1 mol of sucrose(C_12H_22O_11) contains = 11 ×N_A atoms of oxygen

0.01 mol pf sucrose (C_12H_22O_11) =0.01 × 11 ×N_A atoms of oxygen = 0.11 ×N_A atoms of oxygen

Number of moles of water = 18g/18 g mol ¯¹

1 mol of water (H_2O) contains 1 × N_A atom of oxygen

Total number of oxygen atoms = Number of oxygen atoms from sucrose + Number of oxygen atoms from water = 0.11 N_A + 1.0 N_A = 1.11 N_A

Number of oxygen atoms in solution = 1.11 × Avogadro's number

= 1.11 × 6.022 ×10²³

= 6.68 × 10²³

Thus, Number of oxygen atoms in solution = 6.68 × 10²³