Question

3.42 kg of glucose are dissolved in 18g of water in a beaker . The number of oxygen atoms in the solution is

Answer 1

Answer:

No. of Atoms = Given mass/ Molar mass *Avagadro's no.

No. of Oxygen atoms in Glucose molecule = 6

Molar mass of 6 atoms of oxygen = 6*16 = 96

Therefore, No. of atoms in 3.42kg of glucose = 3420/96 * 6.022 * 10^23

= 35.625 * 6.022*10^23 atoms of oxygen in 3.42kg of glucose

No. of oxygen atoms on Water = 1

now, in 18g of of water, no. of oxygen atoms = 18/16 * 6.022 * 10^23

= 1.125 * 6.022 * 10^23

Total no. of atoms in solution = 35.625 * 6.022*10^23 + 1.125 * 6.022 * 10^23

= 36.75 * 36.625 * 10^23

= 1345.97 * 10^23 atoms of oxygen