3.42g of sucrose are dissolved in 18g of water in a beaker. Find the number of oxygen atoms present in the solution
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C12H22O11 + H2O = 2C6H12O6
0.1 mole of sucrose contains = 11 x 0.623 x 10²³ oxygen atoms
1 mole of water contains = 1 x 6.023 x 10²³ oxygen atoms
So , Total number of oxygen atoms would be
11 x 0.623 x 10²³ + 1 x 6.023 x 10²³ = 12.65 x 10²³ atoms.
0.1 mole of sucrose contains = 11 x 0.623 x 10²³ oxygen atoms
1 mole of water contains = 1 x 6.023 x 10²³ oxygen atoms
So , Total number of oxygen atoms would be
11 x 0.623 x 10²³ + 1 x 6.023 x 10²³ = 12.65 x 10²³ atoms.
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