3.49g of ammonia at stp occupies volume of 4.48 dm3 calculate the molar mass of ammonia
Answers
Answered by
196
volume = 4.48 dm3 = 4.48 L
gram molecular mass = 22.4 L at STP
so, 4.48 L of ammonia gas weighs= 3.49 g
22.4 L of ammonia weighs = 22.4 x 3.49 /4.48
= 17.45 g
gram molecular mass = 22.4 L at STP
so, 4.48 L of ammonia gas weighs= 3.49 g
22.4 L of ammonia weighs = 22.4 x 3.49 /4.48
= 17.45 g
Answered by
91
Relative molar mass of ammonia is to be calculated instead of molar mass.
4.48 dm³ = 4.48 L
As we know,
Gram molecular mass = 22.4 L at STP
Thus we can say that,
4.48 L of ammonia gas weighs 3.49 g
22.4 mL of gas will weigh = 22.4 × 3.49 ÷ 4.48
= 17.45 g
Hence relative molar mass of gas Ammonia is 17.45 g
4.48 dm³ = 4.48 L
As we know,
Gram molecular mass = 22.4 L at STP
Thus we can say that,
4.48 L of ammonia gas weighs 3.49 g
22.4 mL of gas will weigh = 22.4 × 3.49 ÷ 4.48
= 17.45 g
Hence relative molar mass of gas Ammonia is 17.45 g
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