3.4gm of H2O2 decomposes the weight of oxygen liberated is
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We first write the equation for the decomposition as follows:
H₂O₂ (aq) -------> 2 H₂O (l) + O₂ (g)
The moles of H₂O₂ decomposing are :
Molar mass of hydrogen peroxide is :
32 + 2 = 3g/mol
moles are :
3.4/34 = 0.1 moles.
The mole ratio of hydrogen peroxide to oxygen is :
2 : 1
The moles of oxygen liberated is thus:
0.1/2 = 0.05 moles
weight of oxygen liberated is thus :
molar mass of oxygen gas = 32
0.05 × 32 = 1.6 grams
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