Question

(3-4i) (2+5i) in a+ib form​

Answer 1

(3-4i)(2+5i) = 3(2) +3(5i) -4i(2) -4i(5i)

= 6 + 15i -8i -20(i)^2

= 6 + 7i -20(-1)

= 6 + 7i + 20

= 26 + 7i

Hence, (3-4i)(2+5i) = 26 + 7i

Answer 2

(3-4i)(2+5i) = 3(2) +3(5i) -4i(2) -4i(5i)

= 6 + 15i -8i -20(i)^2

= 6 + 7i -20(-1)

= 6 + 7i + 20

= 26 + 7i