(3-4sin^2θ) (sec^2θ-4tan^2θ)=(3-tan^2θ)(1-4sin^2θ)
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Answer:
LHS=
cos
2
θ
3−4sin
2
θ
3sec
2
θ−4tan
2
θ
3(1+tan
2
θ)−4tan
2
θ
3+3tan
2
θ−4tan
2
θ
3−tan
2
θ=RHS
Step-by-step explanation:
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