Math, asked by noorfatima25689, 2 months ago

x^2-3x-1=0 by using quadratic formula​

Answers

Answered by khuswinder912
0

Answer:

7iju

Step-by-step explanation:

//98i69797

Answered by cranchgirls
0

Answer:

Use the quadratic formula

=−±2−4√2

x=\frac{-{\color{#e8710a}{b}} \pm \sqrt{{\color{#e8710a}{b}}^{2}-4{\color{#c92786}{a}}{\color{#129eaf}{c}}}}{2{\color{#c92786}{a}}}x=2a−b±b2−4ac

Once in standard form, identify a, b and c from the original equation and plug them into the quadratic formula.

2−3−1=0

x^{2}-3x-1=0x2−3x−1=0

=1

a={\color{#c92786}{1}}a=1

=−3

b={\color{#e8710a}{-3}}b=−3

=−1

c={\color{#129eaf}{-1}}c=−1

=−(−3)±(−3)2−4⋅1(−1)√2⋅1

x=\frac{-({\color{#e8710a}{-3}}) \pm \sqrt{({\color{#e8710a}{-3}})^{2}-4 \cdot {\color{#c92786}{1}}({\color{#129eaf}{-1}})}}{2 \cdot {\color{#c92786}{1}}}x=2⋅1−(−3)±(−3)2−4⋅1(−1)

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