Question

(3/4x-3)-(2/2x+5)=0 solve the equation

Answer 1

$(3 \div 4x - 3 ) - (2 \div 2x + 5) = 0 \\ = >( 3 - 12x \div 4x) + ( - 1 - 5x \div x) = 0\\ 3 - 12x - 4 - 20x \div 4x = 0 \\ = > - 1 - 32x = 0 \\ = > x = - 1 \div 32$
I hope this will help you