Question

(3/4x +4/3y)*(3/4x +3/4z)
solve plz​

Answer 1

Step-by-step explanation:

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Answer 2

The simplified expression would be $\dfrac{9}{16}x^2+xy+\dfrac{9}{16}xz+yz$

Explanation:

Distributive property = a(b+c) = ab + ac  , where a  , b , c be any expression.

The given expression : $(\dfrac{3}{4}x+\dfrac{4}{3}y) \times (\dfrac{3}{4}x+\dfrac{3}{4}z)$

By distributive property ,this would be equal to

$(\dfrac{3}{4}x+\dfrac{4}{3}y) \times\dfrac{3}{4}x+(\dfrac{3}{4}x+\dfrac{4}{3}y) \times\dfrac{3}{4}z$

Again by distributive property , we get

$\dfrac{3}{4}x\times\dfrac{3}{4}x+\dfrac{4}{3}y \times\dfrac{3}{4}x+\dfrac{3}{4}x \times\dfrac{3}{4}z+\dfrac{4}{3}y\times\dfrac{3}{4}z$

Simplify,

$\dfrac{9}{16}x^2+xy+\dfrac{9}{16}xz+yz$

Therefore , the simplified expression would be : $\dfrac{9}{16}x^2+xy+\dfrac{9}{16}xz+yz$

# Learn more :

2x-3y+4z)-(x+3y-4z)+(4x-y+9z)+(-2x+3y-z)

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