Question

(-3-5),(3-2),(2,3) area of triangle​

Answer 1

Answer:

Correct option is

D

5 sq.unit

Area of a triangle with vertices (x

1

,y

1

); (x

2

,y

2

) and (x

3

,y

3

)

=

∣

∣

∣

∣

∣

2

x

1

(y

2

−y

3

)+x

2

(y

3

−y

1

)+x

3

(y

1

−y

2

)

∣

∣

∣

∣

∣

Hence, substituting the points (x

1

,y

1

)=(3,2) ; (x

2

,y

2

)=(−2,−3) and (x

3

,y

3

)=(2,3)

in the area formula, we get

Area =

∣

∣

∣

∣

∣

2

3(−3−3)+(−2)(3−2)+2(2−(−3))

∣

∣

∣

∣

∣

=5 sq. unit