Question

3/5^3 * 3/5^-6=3/5^2x-1 find x??

Answer 1

Hey friend!!

Here's ur answer...


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$( \frac{3}{5} {)}^{3} \times ( \frac{3}{5} {)}^{ - 6} = ( \frac{3}{5} {)}^{2x - 1} \\ \\ ( \frac{3}{5} {)}^{ - 3 } = ( \frac{3}{5} {)}^{2x - 1} \\ \\ - 3 = 2x - 1 \\ 2x = - 2 \\ x = - 1$


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Hope it may help you...


Thank you :) :))

Answer 2

Hey Friend ☺

☆ INDICES ☆

You have to know

a^m × a^n = a^m + n

The value of x is -1

Hope it helps you ..!!

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