Math, asked by AnkitSarkar, 1 year ago

3/5^3 * 3/5^-6=3/5^2x-1 find x??

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Answered by Anonymous
4
Hey friend!!

Here's ur answer...


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( \frac{3}{5}  {)}^{3}  \times ( \frac{3}{5}  {)}^{ - 6}  = ( \frac{3}{5}  {)}^{2x - 1}  \\  \\ ( \frac{3}{5}  {)}^{ - 3 }  = ( \frac{3}{5}  {)}^{2x - 1}  \\   \\  - 3 = 2x - 1 \\ 2x =  - 2 \\  x =  - 1


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Hope it may help you...


Thank you :) :))

AnkitSarkar: brainliest
AnkitSarkar: hahaha
Answered by QUEEN007
7
Hey Friend ☺

☆ INDICES ☆

You have to know

a^m × a^n = a^m + n

The value of x is -1

Hope it helps you ..!!

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