Math, asked by StarTbia, 1 year ago

3√5/5√7,√63/√125 Compare the given pairs of ratio.

Answers

Answered by tanmay5474
12
they are in descending order
Answered by 23saurabhkumar
35

Answer:

\frac{\sqrt{63}}{\sqrt{125}}>\frac{3\sqrt{5}}{5\sqrt{7}}

Step-by-step explanation:

In the given question,

We have two ratios,\frac{3\sqrt{5}}{5\sqrt{7}} and \frac{\sqrt{63}}{\sqrt{125}}.

Here, we have to compare the two ratios.

For comparing the ratios we have to calculate the value of all the ratios individually.

So, on calculating the value of the ratios we get,

\frac{3\sqrt{5}}{5\sqrt{7}}=0.507

And,

The value of another ratio is given by,  

\frac{\sqrt{63}}{\sqrt{125}}=0.5291

So,

We can say that the ratio \frac{\sqrt{63}}{\sqrt{125}} is greater than  \frac{3\sqrt{5}}{5\sqrt{7}}.

So,

\frac{\sqrt{63}}{\sqrt{125}}>\frac{3\sqrt{5}}{5\sqrt{7}}

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