Question

3 ਮੀ. ਅਤੇ 5 ਮੀ. ਲੰਬੀਆਂ ਦੋ ਸੋਟੀਆਂ ਇਸ ਤਰ੍ਹਾਂ ਕੱਟਦੀਆਂ ਹਨ ਕਿ ਲੰਬੀ ਸੋਟੀ ਛੋਟੀ ਸੋਟੀ ਨੂੰ 90° ਤੇ ਸਮਦੁਭਾਜਿਤ ਕਰਦੀ ਹੈ । ਇਨ੍ਹਾਂ ਦੇ ਅੰਤ ਬਿੰਦੂਆਂ ਨੂੰ ਮਿਲਾਉਣ ਤੇ ਕਿਹੜੀ ਆਕ੍ਰਿਤੀ ਬਣੇਗੀ

Answer 1

Given :- Length of two sticks is 3 m and 5m and they are crossing each other such that longer stick bisect shorter stick at 90 degree.

To Find :- Which shape the is formed by joining their end points ?

A) square

B) rectangle

C) rhombus

D) kite .

Solution :-

given that, length of both sticks is different as 3 m and 5m and only longer stick bisect shorter stick .

Now we know that,

In a parallelogram both diagonals bisect each other .

so, checking given options ,

A) Square = A parallelogram whose all sides are equal and both diagonals bisect each other . Therefore, this shape is not possible .

B) Rectangle = A parallelogram whose opposite sides are equal and both diagonals bisect each other . Therefore, this shape is not possible .

C) Rhombus = A parallelogram whose all sides are equal and both diagonals bisect each other at 90° . But since we have given that, that longer stick bisect shorter stick . Therefore, this shape is not possible .

D) kite = A quadrilateral whose diagonals are perpendicular (90°) and longer diagonal bisect shorter diagonal only .

since we have given that, both sticks cross each other at 90° and longer stick bisect shorter stick .

therefore, we can conclude that, the shape formed by joining the end points of sticks of 3m and 5m will form a (D) kite .

Extra :-

some properties of kite :-

Adjacent sides are equal .

Only one pair of opposite angle is equal .

Diagonals are perpendicular and longer diagonal also bisect shorter diagonal .

Area = (1/2) * D1 * D2 { where D1 and D2 are diagonals. }

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