Question

3 (5a – 2 b
Please help me with this #algebra sum

Answer 1

Given: The equation is$3(5a-2b)$.

We have to solve the above equation.

To solve the above equation, we will follow the BODMAS rule.

As we know that it is the rule used to remember the order of operations to be followed while solving expressions in mathematics.

where,

$\begin{array}{l}\mathrm{B}=\text{brackets}\\\mathrm{O}=\text { order of powers or rules } \\\mathrm{D}=\text { division } \\\mathrm{M}=\text { multiplication } \\\mathrm{A}=\text { addition } \\\mathrm{S}=\text { subtraction }\end{array}$

We are solving in the following way:

We have,

=> $3(5a-2b)$

$=>15a-6b$

Hence, after solving the above equation we get, the solution of the equation is$15a-6b$.

Answer 2

Answer:

By simplifying $3 (5a -2 b)$ we get $15a - 6b$.

Step-by-step explanation:

To find

simplified form of  $3 (5a -2 b)$

Solution-

As it is given in the question,

As here we have to simplify the like terms, so, we will operate the terms containing "a" with them and other constant with constant.

For simplifying we will use BODMAS,

As per BODMAS rule,

B for Bracket

O for Of

D for Divide

M for Multiply

A for Addition

S for Subtraction

So, applying the above concept,

We have to first do the multiplication of 3

$= 3$ × $(5a -2 b)$

= $15 a -6b$

By simplifying $3 (5a -2 b)$ we get $15a - 6b$.