Question

3+5i / 2-3i express in the form a+bi​

Answer 1

3+5i/2-3i

= 3+5i/2-3i × 2+3i/2+3i

= 3(2+3i) + 5i(2+3i)/(2-3i)(2+3i)

=6+9i + 10i + 15i²/(2)²- (3i)².

( since,(a+b)(a-b)=a²-b² )

=19i+6+15i²/4-9i². ( since,i²= -1 )

=(19i+6-15)/4+9

=(19i-9)/13

= -9/13 + i19/3 which is of form a+ib.