Question

3-5x/3-4x=-5x+1/5x-1 solve the equation

Answer 1

take negative sign common from R.H.S so that numerator nd denominator becomes equal nd cancels than cross multiply nd solve to get x=2/3.

Answer 2

Question :-

$\bf\underline{\underline{\orange{ Solve:-}}}$

$\dfrac{3 \: - \: 5x}{3 \: - \: 4x} \: = \: \dfrac{ - 5x \: + \: 1}{5x \: - \: 1}$

Solution :-

$\qquad \quad \longrightarrow \sf \boxed{\bf{\dfrac{3 \: - \: 5x}{3 \: - \: 4x} \: = \: \dfrac{ - 5x \: + \: 1}{5x \: - \: 1}}}$

$\qquad \quad \longrightarrow \sf {\sf{\dfrac{3 \: - \: 5x}{3 \: - \: 4x} \: = \: \cancel\dfrac{ - 5x \: + \: 1}{5x \: - \: 1}}}$

$\qquad \quad \longrightarrow \sf {\sf{\dfrac{3 \: - \: 5x}{3 \: - \: 4x} \: = \: \dfrac{ - 1}{1}}}$

Now, Using Cross Multiplaction.

$\qquad \quad \longrightarrow \sf {\sf{1(3 - 5x) \: = \: - 1(3 - 4x)}}$

$\qquad \quad \longrightarrow \sf {\sf{3 \: - \: 5x\: = \: - 3 \: + \: 4x}}$

$\qquad \quad \longrightarrow \sf {\sf{3 \: + \: 3\: = \: 5x \: + \: 4x}}$

$\qquad \quad \longrightarrow \sf {\sf{6\: = \: 9x}}$

$\qquad \quad \longrightarrow \sf {\sf{ \dfrac{6}{9} \: = \: x}}$

$\qquad \quad \longrightarrow \sf {\sf{ \cancel\dfrac{6}{9} \: = \: x}}$

$\qquad \quad \longrightarrow \sf \boxed{\bf{ \dfrac{2}{3} \: = \: x}}$