Question

((3^-6/7)*(4^-3/7)*(9^3/7)*(2^6/7))/(2^2+2^0+2^-2): indices​

Answer 1

Question :- Given above in image .

Solution :- Refer to image .

formula used :-

In first step :-

• (a^m)^n = (a)^(m * n)
• a^(-m) = 1/a^m

In second step :-

• a^m * a^n = a^(m + n)
• a^0 = 1

In third step :-

• Additive inverse .

In fourth step :-

• a^0 = 1 { so, 1 + 1 = 2 }

therefore,

→ Final answer = (8/21)

Learn more :-

(7sqrt(3))/(sqrt(10+sqrt(3)))-(2sqrt(5))/(sqrt(6)+sqrt(5))-(3sqrt(2))/(sqrt(5)+3sqrt(2))

brainly.in/question/32043164

if the positive square root of (√190 +√ 80) i multiplied by (√2-1) and the

product is raised to the power of four the re...

brainly.in/question/26618255