Question

3,6,9,....99 how many term of the sequence​

Answer 1

The given sequence is an A.P. with first term a=3 and common difference d=3. Let there be n terms in the given sequence. Then,

nth term=99

a+(n−1)d=99

3+(n−1)×3=99

n=33

Thus, the given sequence contains 33 terms

Step-by-step explanation:

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