Question

√3+7/√3-7 + √2-3/√3+7. rationalize....​

Answer 1

Question :---

• solve [(√3)+7]/[(√3)-7] +. [(√2)-3]/[(√3) + 7]

Solution :-------

Taking LCM of denominator we get,

→ [(√3)+7]*[(√3) + 7] + [(√2)-3]*[(√3)-7] / [(√3)-7]*[(√3)+7]

Now we know that,

(a+b)(a-b) = a² - b²

(a+b)(a+b) = (a+b)² = a² + b² + 2ab

using both now we get,,

→ [3 + 49 + 14√3 + √6 -7√2 -3√3 + 21] / (3 - 49)

→ [ 73 +11√3 -7√2 + √6 ] / (-46)

or,

→ (7√2 - 11√3 - √6 - 73) / 46 (Ans) .

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