(3/7)^‐5 × (7/3)^11 therefore find 3/7^k find the value of k
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Answer:
-16
Step-by-step explanation:
(3/7)^-5 ×(7/3)^11 = (3/7)^k
(3/7)^-5 ×(3/7)^-11= (3/7)^k
-5-11=k
k=-16
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