3/7 of 7 KG of apples were used on Monday. The next day 1/4 of rest of the apples was used. Then weight of the apples left now is?
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Option (c) is correct here
From the question it is given that,
4/5 of 5 kg apples were used on Monday = (4/5) × 5
= 20/5
= 4 kg
Then,
The next day 1/3 of what was left was used = (1/3) × 1
= 1/3 kg
So, Weight (in kg) of apples left now is = 1–(1/3)
= (3 - 1)/3
= 2/3 kg of apples
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