-3/7×p/q=1 find the value of pq
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0
Answer:
19
Step-by-step explanation:
Given, p+q=2 and pq=1,
So, (p−q)
2
=(p+q)
2
−4pq
⇒(p−q)
2
=2
2
−4=0
⇒(p−q)=0
or p=q As, p+q=2⇒p=q=1
Hence, p
3
+q
3
+6p
2
+5q
2
+6pq=1+1+6+5+6=19
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