Question

3^73+7^37.find digit in unit place​

Answer 1

Answer:

6.76037608e34.

hope this will help you.

Answer 2

The digit in unit place=0

Step-by-step explanation:

$3^1=3$

$3^2=9$

$3^3=27$ Unit digit is 7

$3^4=81$

Units digit=1

$3^5=243$

Unit digit=3

Cycle of 3=4

$7^1=7$

$7^2=49$

Unit digit=9

$7^3=343$

Unit digit=3

$7^4=2401$

Unit digit=1

$7^5=16807$

Units digit=7

Cycle of 7=4

Power of 3=73

Remainder =$\frac{73}{4}=1$

It means unit digit is 3 when $3^{73}$

Power of 7=37

Remainder=$\frac{37}{4}=1$

It means unit digit is 7 when remainder is 1.

Unit digit is 7 when $7^{37}$

$3+7=10$

Units digit=0

Hence, the digit in unit place=0

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