Question

3 ( 7x+1/ 5x-3) - 4 ( 5x-3/ 7x+1) = 11 solve for x

Answer 1

3(7x+1/5x-3) - 4 (5x-3/7x+1)= 11

On Putting 7x+1/5x-3 = y,

3y - 4/y = 11

(3y × y -4 ) / y = 11

3y² - 4 = 11y

3y² - 11 y - 4 = 0

3y² -12y + y - 4 = 0

3y ( y - 4) +1(y - 4)= 0

(3y +1) (y - 4)= 0

(3y +1) = 0 or (y - 4)= 0

y = -⅓ or y = 4

Case 1. y = -⅓

7x+1/5x-3 = - ⅓

3(7x+1) = -1(5x-3)

21x +3 = -5x +3

21x +5x = 3 -3

26x = 0

x = 0/26

x = 0

Case 2. y = 4

7x+1/5x-3 = 4

7x+1 = 4(5x-3 )

7x +1 = 20x -12

7x - 20x = -12-1

-13x = -13

x = 13/13

x = 1

Hence, the value of x= 0 or x =

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