Computer Science, asked by Shivampathak710IAF, 1 year ago

3х+ 7y = 31
6х +6y= 34
find x and y by substitution method.​

Answers

Answered by navigugnani
2

3x+7y=31

multiply by 2

6x+14y=62

6x+6y=34

subtraction

8y= 28

y= 28/8

y= 7/2

put the value of y = 7/2 in equation 1

3x+7(7/2) = 31

3x+49/2 =31

3x= 31-49/2

3x= 62-49/2

3x= 13/2

x= 13/2÷3

x= 13/6

Answered by Anonymous
2

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