Question

3,8,27,110,565,3396 which one is wrong

Answer 1

$Given \: sequence : 3,8,27,110,565,3396$

/* Observe the sequence , we find following pattern */

$i ) First \:term (a_{1})$

$= 2\times 1 + 1$

$= 2+1$

$= \blue{3}$

$ii) Second \:term (a_{2})$

$= a_{1}\times 2 + 2$

$= 3 \times 2 + 2$

$= 6 + 2$

$= \pink{8}$

$iii) Third \:term (a_{3})$

$= a_{2}\times 3 + 3$

$= 8 \times 3 + 3$

$= 24 + 3$

$= \pink{27}$

$iv) \red{Fourth \:term (a_{4}) }$

$= a_{3}\times 4 + 4$

$= 27 \times 4 + 4$

$= 108 + 4$

$= \red{112}$

$v) Fifth \:term (a_{5})$

$= a_{4}\times 5+ 5$

$= 112\times 5+ 5$

$=560 + 5$

$= \pink{565}$

$vi) Sixth \:term (a_{6})$

$= a_{5}\times 6+ 6$

$= 565 \times 6+ 6$

$= 3390 + 6$

$= \pink{3396}$

Therefore.,

$\red{ wrong \:one \: in \:the \: sequence } \green { = 110}$

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