Question

3-8
Find the value of K, where K is an integer and 2K+5 x 62K-3 = ---
126 x 2
x 6²K-3​

Answer 1

Answer:

2k+5×'62k-3=126×2×6

${6}^{2}$-k-3

2k+310×k=126×2×(2-3)2k

2k+310×k=126×2×

${2}^{2}$

-

${3}^{2}$

k

k=0