Question

3(a-5)-16a=12-2(a-3)
Please solve

Answer 1

Answer:

$3\left(a-5\right)-16a=12-2\left(a-3\right)\\= -13a-15=-2a+18\\= -13a-15+15=-2a+18+15\\= -13a=-2a+33\\= -13a+2a=-2a+33+2a\\= -11a=33\\= \frac{-11a}{-11}=\frac{33}{-11}\\\\= a=-3$

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Answer 2

Here’s your answer. Hope it helps you