Question

3) A 50 Hz voltage signal is sampled at 3000 Hz, then the phase angle between the two successive samples is
a) 8°
b) 7°
c) 6°
d)9° ​

Answer 1

Answer:

Explanation:

8

Answer 2

Answer:

The answer is closest to option (b) 7°.

Explanation:

The phase angle between two successive samples of a sinusoidal signal can be calculated using the formula:

φ = 360 * (f_s / f) * (t_2 - t_1)

where:

φ is the phase angle in degrees

f_s is the sampling frequency

f is the frequency of the sinusoidal signal

t_2 and t_1 are the times at which the two successive samples are taken

In this case, the frequency of the sinusoidal signal is 50 Hz, and it is sampled at a frequency of 3000 Hz. Therefore, the ratio of the sampling frequency to the signal frequency is:

f_s / f = 3000 / 50 = 60

Assuming that the time difference between two successive samples is 1/3000 seconds, we can calculate the phase angle:

φ = 360 * 60 * 1/3000 = 7.2 degrees

Therefore, the answer is closest to option (b) 7°.

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